LATIN LETTER SMALL CAPITAL BARRED B·U+1D03

Character Information

Code Point
U+1D03
HEX
1D03
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 83
11100001 10110100 10000011
UTF16 (big Endian)
1D 03
00011101 00000011
UTF16 (little Endian)
03 1D
00000011 00011101
UTF32 (big Endian)
00 00 1D 03
00000000 00000000 00011101 00000011
UTF32 (little Endian)
03 1D 00 00
00000011 00011101 00000000 00000000
HTML Entity
ᴃ
URI Encoded
%E1%B4%83

Description

U+1D03, also known as the Latin Letter Small Capital Barred B, is a typographical character that plays a significant role in digital text, specifically within Unicode encoding. It belongs to the Latin Extended-C subset of the Unicode character set and was added in Version 5.0 (June, 2006). This character is often used for specific purposes in linguistics, cryptography, or typography where its distinct visual appearance is needed to convey unique meaning or differentiate from similar characters. Its primary function lies in its small capital form, providing a clear and easily recognizable distinction from the regular uppercase "B" (U+0042) or lowercase "b" (U+0062). However, it's worth noting that this character is not widely used across digital platforms due to its specialized nature.

How to type the symbol on Windows

Hold Alt and type 7427 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D03. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D03 to binary: 00011101 00000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10000011