LATIN LETTER SMALL CAPITAL L WITH STROKE·U+1D0C

Character Information

Code Point
U+1D0C
HEX
1D0C
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 8C
11100001 10110100 10001100
UTF16 (big Endian)
1D 0C
00011101 00001100
UTF16 (little Endian)
0C 1D
00001100 00011101
UTF32 (big Endian)
00 00 1D 0C
00000000 00000000 00011101 00001100
UTF32 (little Endian)
0C 1D 00 00
00001100 00011101 00000000 00000000
HTML Entity
ᴌ
URI Encoded
%E1%B4%8C

Description

The Unicode character U+1D0C represents the "LATIN LETTER SMALL CAPITAL L WITH STROKE". In digital text, this character is primarily used in typography and design for its unique appearance, which differentiates it from a standard lowercase 'L'. It features a horizontal stroke through the middle of the letter, giving it a distinct visual style that can be utilized to enhance readability or aesthetic appeal. While the LATIN LETTER SMALL CAPITAL L WITH STROKE is not commonly used in everyday language, it may appear in specialized contexts such as programming languages, mathematical notation, or when creating custom fonts for specific purposes. Its usage reflects the broader role of Unicode, which aims to provide a comprehensive character set for representing text from all writing systems across the world.

How to type the symbol on Windows

Hold Alt and type 7436 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D0C. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D0C to binary: 00011101 00001100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10001100