LATIN LETTER SMALL CAPITAL OPEN O·U+1D10

Character Information

Code Point
U+1D10
HEX
1D10
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 90
11100001 10110100 10010000
UTF16 (big Endian)
1D 10
00011101 00010000
UTF16 (little Endian)
10 1D
00010000 00011101
UTF32 (big Endian)
00 00 1D 10
00000000 00000000 00011101 00010000
UTF32 (little Endian)
10 1D 00 00
00010000 00011101 00000000 00000000
HTML Entity
ᴐ
URI Encoded
%E1%B4%90

Description

The Unicode character U+1D10, known as "LATIN LETTER SMALL CAPITAL OPEN O," is a unique typographical element that serves a specific purpose in digital text. This character is an uppercase version of the letter 'O' with an open-style appearance, resembling a lowercase 'o.' Its primary usage can be found within typographic design and certain niche applications where the distinction between uppercase and lowercase letters is desired for stylistic purposes. However, it is crucial to note that this character is not commonly used in everyday language or traditional typography, as it may cause confusion among readers who are accustomed to standard letterforms. The LATIN LETTER SMALL CAPITAL OPEN O holds a niche position within the vast landscape of Unicode characters, reflecting its unique role in digital text.

How to type the symbol on Windows

Hold Alt and type 7440 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D10. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D10 to binary: 00011101 00010000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10010000