LATIN LETTER SMALL CAPITAL REVERSED N·U+1D0E

Character Information

Code Point
U+1D0E
HEX
1D0E
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 8E
11100001 10110100 10001110
UTF16 (big Endian)
1D 0E
00011101 00001110
UTF16 (little Endian)
0E 1D
00001110 00011101
UTF32 (big Endian)
00 00 1D 0E
00000000 00000000 00011101 00001110
UTF32 (little Endian)
0E 1D 00 00
00001110 00011101 00000000 00000000
HTML Entity
ᴎ
URI Encoded
%E1%B4%8E

Description

U+1D0E is the Unicode code point for the Latin Letter Small Capital Reversed N (ᚐ). This character is primarily used in typography to represent a reversed version of the capital letter "N" within digital text, particularly when adhering to specific design requirements or conventions. In certain fonts and typefaces, it may serve as an alternative glyph for the standard capital letter "N". U+1D0E holds no specific cultural or linguistic significance, but it plays a functional role in typography by providing designers with an additional option to vary the appearance of text. The Latin Letter Small Capital Reversed N is part of the Unicode Standard, which aims to accommodate a wide range of characters and symbols from various writing systems for global communication and representation.

How to type the symbol on Windows

Hold Alt and type 7438 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D0E. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D0E to binary: 00011101 00001110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10001110