LATIN LETTER SMALL CAPITAL Z·U+1D22

Character Information

Code Point
U+1D22
HEX
1D22
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 A2
11100001 10110100 10100010
UTF16 (big Endian)
1D 22
00011101 00100010
UTF16 (little Endian)
22 1D
00100010 00011101
UTF32 (big Endian)
00 00 1D 22
00000000 00000000 00011101 00100010
UTF32 (little Endian)
22 1D 00 00
00100010 00011101 00000000 00000000
HTML Entity
ᴢ
URI Encoded
%E1%B4%A2

Description

U+1D22 is the Unicode code point for the Latin letter Small Capital Z. This character is used in digital texts to represent a lowercase version of the letter 'Z' with an elevated capitalization style, commonly known as small capitals. Although not widely used in modern English typography, small capitals were prevalent in traditional print and manuscript works, particularly in the context of fine arts, design, and historical documents. The Latin script, which includes the letter Z, has its origins dating back to the Roman Empire, making it one of the most enduring writing systems in human history. In digital text, U+1D22 can be utilized to maintain a consistent stylistic format or to adhere to specific design preferences and conventions.

How to type the symbol on Windows

Hold Alt and type 7458 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D22. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D22 to binary: 00011101 00100010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10100010