LATIN SMALL LETTER B WITH PALATAL HOOK·U+1D80

Character Information

Code Point
U+1D80
HEX
1D80
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 80
11100001 10110110 10000000
UTF16 (big Endian)
1D 80
00011101 10000000
UTF16 (little Endian)
80 1D
10000000 00011101
UTF32 (big Endian)
00 00 1D 80
00000000 00000000 00011101 10000000
UTF32 (little Endian)
80 1D 00 00
10000000 00011101 00000000 00000000
HTML Entity
ᶀ
URI Encoded
%E1%B6%80

Description

U+1D80, also known as the Latin Small Letter B with Palatal Hook, is a typographical character used in Unicode-compliant digital text systems. This letter represents a specific sound or phoneme in certain languages and dialects, particularly those influenced by or derived from Spanish and Portuguese. The Palatal Hook character adds a unique visual flair to the traditional "b" shape, setting it apart from other Latin script characters. It is commonly used in linguistic, cultural, and historical studies as well as typography projects that aim to explore and showcase the richness and diversity of global writing systems. In these contexts, U+1D80 provides an accurate representation of the phonetic nuances found in various regional dialects and languages, promoting a more inclusive and comprehensive understanding of human communication.

How to type the symbol on Windows

Hold Alt and type 7552 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D80. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D80 to binary: 00011101 10000000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10000000