LATIN SMALL LETTER INSULAR G·U+1D79

Character Information

Code Point
U+1D79
HEX
1D79
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B5 B9
11100001 10110101 10111001
UTF16 (big Endian)
1D 79
00011101 01111001
UTF16 (little Endian)
79 1D
01111001 00011101
UTF32 (big Endian)
00 00 1D 79
00000000 00000000 00011101 01111001
UTF32 (little Endian)
79 1D 00 00
01111001 00011101 00000000 00000000
HTML Entity
ᵹ
URI Encoded
%E1%B5%B9

Description

U+1D79 is the Unicode code point for the character "LATIN SMALL LETTER INSULAR G." This character is part of the Extended Latin alphabet, which extends the basic Latin script with additional characters for various languages and regional dialects. The typical usage of this character in digital text is to represent the lowercase version of the letter "G" in the Insular alphabet, a variant used primarily in Ireland during the Middle Ages. Although not widely used today in mainstream language or typography, it holds significance for linguists, historians, and those studying medieval Irish manuscripts. The character's inclusion in Unicode ensures its preservation and accessibility for future generations to study and appreciate its historical and cultural context.

How to type the symbol on Windows

Hold Alt and type 7545 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D79. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D79 to binary: 00011101 01111001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110101 10111001