LATIN SMALL LETTER R WITH FISHHOOK AND MIDDLE TILDE·U+1D73

Character Information

Code Point
U+1D73
HEX
1D73
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B5 B3
11100001 10110101 10110011
UTF16 (big Endian)
1D 73
00011101 01110011
UTF16 (little Endian)
73 1D
01110011 00011101
UTF32 (big Endian)
00 00 1D 73
00000000 00000000 00011101 01110011
UTF32 (little Endian)
73 1D 00 00
01110011 00011101 00000000 00000000
HTML Entity
ᵳ
URI Encoded
%E1%B5%B3

Description

U+1D73, also known as LATIN SMALL LETTER R WITH FISHHOOK AND MIDDLE TILDE, is a character from the Unicode standard that plays a vital role in digital text representation. This unique typographical symbol combines two distinct diacritical marks, the fishhook and the middle tilde, with the letter "r." Its primary usage can be found in various languages that employ these special characters to represent specific phonetic or orthographic features. The character's cultural and linguistic significance lies in its ability to differentiate particular sounds within a language, aiding in accurate communication and understanding among speakers of those languages. In technical contexts, U+1D73 is employed by typographers, graphic designers, and developers who seek to incorporate culturally diverse scripts or create visually unique content for digital platforms, adhering to the principles of typographic accuracy and legibility.

How to type the symbol on Windows

Hold Alt and type 7539 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D73. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D73 to binary: 00011101 01110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110101 10110011