LATIN SMALL LETTER SIDEWAYS TURNED M·U+1D1F

Character Information

Code Point
U+1D1F
HEX
1D1F
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 9F
11100001 10110100 10011111
UTF16 (big Endian)
1D 1F
00011101 00011111
UTF16 (little Endian)
1F 1D
00011111 00011101
UTF32 (big Endian)
00 00 1D 1F
00000000 00000000 00011101 00011111
UTF32 (little Endian)
1F 1D 00 00
00011111 00011101 00000000 00000000
HTML Entity
ᴟ
URI Encoded
%E1%B4%9F

Description

U+1D1F, or Latin Small Letter Sideways Turned M, is a unique Unicode character that holds significance in the realm of typography and digital text. This particular symbol represents an inverted version of the letter 'M', with the stroke of the letter rotated 180 degrees. Its primary usage lies within typographical designs, where it serves as a decorative element to add flair and visual interest. It is not commonly used for linguistic purposes but can be found in various contexts such as emojis, logos, or design elements in digital media. The character showcases the flexibility and diversity of the Unicode system, which allows for a wide range of symbols and characters beyond the standard alphanumeric set, fostering creativity and expression in digital text.

How to type the symbol on Windows

Hold Alt and type 7455 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D1F. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D1F to binary: 00011101 00011111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10011111