LATIN SMALL LETTER TURNED OPEN E·U+1D08

Character Information

Code Point
U+1D08
HEX
1D08
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 88
11100001 10110100 10001000
UTF16 (big Endian)
1D 08
00011101 00001000
UTF16 (little Endian)
08 1D
00001000 00011101
UTF32 (big Endian)
00 00 1D 08
00000000 00000000 00011101 00001000
UTF32 (little Endian)
08 1D 00 00
00001000 00011101 00000000 00000000
HTML Entity
ᴈ
URI Encoded
%E1%B4%88

Description

U+1D08 is a Unicode character that represents the Latin Small Letter Turned Open E (ᛁ). In digital text, it is typically used for its distinctive form in typography, particularly within the context of runic scripts. This character is one of the 33 Old English or Anglo-Saxon characters from the Futhorc runic alphabet, which was widely used by Germanic tribes in Northern Europe during the early Middle Ages. U+1D08 holds cultural significance as it reflects the rich history and linguistic heritage of these ancient societies. It is primarily utilized for educational purposes, historical research, and creative works involving runic scripts to maintain accuracy and authenticity within specific cultural contexts.

How to type the symbol on Windows

Hold Alt and type 7432 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D08. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D08 to binary: 00011101 00001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10001000