MODIFIER LETTER CAPITAL L·U+1D38

Character Information

Code Point
U+1D38
HEX
1D38
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 B8
11100001 10110100 10111000
UTF16 (big Endian)
1D 38
00011101 00111000
UTF16 (little Endian)
38 1D
00111000 00011101
UTF32 (big Endian)
00 00 1D 38
00000000 00000000 00011101 00111000
UTF32 (little Endian)
38 1D 00 00
00111000 00011101 00000000 00000000
HTML Entity
ᴸ
URI Encoded
%E1%B4%B8

Description

The Unicode character U+1D38 represents the Modifier Letter Capital L (ꞅ). This character is part of a set of letters designed to be used in conjunction with other characters to form accented or otherwise modified versions of those base characters. In digital text, U+1D38 is typically employed as a modifier for specific languages and alphabets that require its unique characteristics. For instance, it can be used to create the uppercase letter "L" with a dotless i (꞉) or the IPA symbol for the voiceless alveolar lateral fricative /ɬ/ in phonetics. While this character might not have significant cultural or linguistic context, it is an essential tool for typographers and linguists working with specific languages that utilize these unique letter modifications. U+1D38 ensures accurate representation of the intended sound or meaning, contributing to clear communication and understanding across different languages and alphabets.

How to type the symbol on Windows

Hold Alt and type 7480 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D38. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D38 to binary: 00011101 00111000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10111000