MODIFIER LETTER CAPITAL REVERSED E·U+1D32

Character Information

Code Point
U+1D32
HEX
1D32
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 B2
11100001 10110100 10110010
UTF16 (big Endian)
1D 32
00011101 00110010
UTF16 (little Endian)
32 1D
00110010 00011101
UTF32 (big Endian)
00 00 1D 32
00000000 00000000 00011101 00110010
UTF32 (little Endian)
32 1D 00 00
00110010 00011101 00000000 00000000
HTML Entity
ᴲ
URI Encoded
%E1%B4%B2

Description

The Unicode character U+1D32, known as the Modifier Letter Capital Reversed E (ↂ), is a typographical symbol primarily used in digital text for its specific role within the International Phonetic Alphabet (IPA). It serves as a diacritic modifier to alter the pronunciation of a preceding consonant, indicating that it should be pronounced with an ejective release. In linguistic and phonetic contexts, this character is essential for accurate transcription and representation of spoken language, particularly for those working in fields such as linguistics, foreign languages, speech therapy, or translation. Although its usage may be somewhat niche, the Modifier Letter Capital Reversed E plays a crucial role in ensuring precise communication and understanding within these disciplines.

How to type the symbol on Windows

Hold Alt and type 7474 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D32. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D32 to binary: 00011101 00110010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10110010