MODIFIER LETTER CAPITAL REVERSED N·U+1D3B

Character Information

Code Point
U+1D3B
HEX
1D3B
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 BB
11100001 10110100 10111011
UTF16 (big Endian)
1D 3B
00011101 00111011
UTF16 (little Endian)
3B 1D
00111011 00011101
UTF32 (big Endian)
00 00 1D 3B
00000000 00000000 00011101 00111011
UTF32 (little Endian)
3B 1D 00 00
00111011 00011101 00000000 00000000
HTML Entity
ᴻ
URI Encoded
%E1%B4%BB

Description

U+1D3B is the Unicode code point for Modifier Letter Capital Reversed N (Ꞇ). This typographic character is primarily used in digital text to modify certain letters by reversing their vertical orientation, specifically within the Latin Extended-B set of Unicode. Its role is predominantly technical, serving as a helpful tool for typographers and designers who work with scripts that require such modifications. It is not tied to any specific cultural, linguistic, or regional contexts, but rather provides flexibility in character composition for specific design or visual requirements within digital text. The Modifier Letter Capital Reversed N (Ꞇ) enables typographers to create unique and innovative typefaces by altering the orientation of certain letters, thus enhancing the visual appeal of a text or design without changing its content or meaning.

How to type the symbol on Windows

Hold Alt and type 7483 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D3B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D3B to binary: 00011101 00111011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10111011