MODIFIER LETTER SMALL A·U+1D43

Character Information

Code Point
U+1D43
HEX
1D43
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B5 83
11100001 10110101 10000011
UTF16 (big Endian)
1D 43
00011101 01000011
UTF16 (little Endian)
43 1D
01000011 00011101
UTF32 (big Endian)
00 00 1D 43
00000000 00000000 00011101 01000011
UTF32 (little Endian)
43 1D 00 00
01000011 00011101 00000000 00000000
HTML Entity
ᵃ
URI Encoded
%E1%B5%83

Description

The Unicode character U+1D43, known as the Modifier Letter Small A, serves a unique purpose within the realm of typography and digital text. This character is not commonly used in everyday writing but holds significance for specific applications. It is often employed to modify letters or other characters, particularly in phonetic transcription systems like the International Phonetic Alphabet (IPA). In these contexts, U+1D43 can be utilized to indicate a specific pronunciation rule or to denote a particular linguistic feature. Despite its limited usage in general writing, the Modifier Letter Small A plays an essential role in accurately representing and preserving language nuances within specialized fields like linguistics, phonetics, and translation.

How to type the symbol on Windows

Hold Alt and type 7491 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D43. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D43 to binary: 00011101 01000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110101 10000011