MODIFIER LETTER SMALL TOP HALF O·U+1D54

Character Information

Code Point
U+1D54
HEX
1D54
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B5 94
11100001 10110101 10010100
UTF16 (big Endian)
1D 54
00011101 01010100
UTF16 (little Endian)
54 1D
01010100 00011101
UTF32 (big Endian)
00 00 1D 54
00000000 00000000 00011101 01010100
UTF32 (little Endian)
54 1D 00 00
01010100 00011101 00000000 00000000
HTML Entity
ᵔ
URI Encoded
%E1%B5%94

Description

The character U+1D54, known as the Modifier Letter Small Top Half O, is a typographical element found within the Unicode Standard. In digital text, this character is primarily employed for phonetic transcription purposes, particularly in linguistic fields such as phonology and phonetics. It serves to represent an open-mid position of articulation in speech sounds, specifically when combined with other letters that depict manner of articulation. While it may appear in various contexts within these specific disciplines, the Modifier Letter Small Top Half O holds a niche purpose rather than widespread utilization. Its role is confined to specialized areas of language study and does not carry notable cultural, linguistic, or technical significance beyond these fields.

How to type the symbol on Windows

Hold Alt and type 7508 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D54. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D54 to binary: 00011101 01010100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110101 10010100