MODIFIER LETTER SMALL TURNED M·U+1D5A

Character Information

Code Point
U+1D5A
HEX
1D5A
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B5 9A
11100001 10110101 10011010
UTF16 (big Endian)
1D 5A
00011101 01011010
UTF16 (little Endian)
5A 1D
01011010 00011101
UTF32 (big Endian)
00 00 1D 5A
00000000 00000000 00011101 01011010
UTF32 (little Endian)
5A 1D 00 00
01011010 00011101 00000000 00000000
HTML Entity
ᵚ
URI Encoded
%E1%B5%9A

Description

U+1D5A, the Modifier Letter Small Turned M, is a typographical character within the Unicode Standard. It serves as a modifier for various purposes in digital text, often found in linguistic contexts that require diacritical marks or accents. This character, which appears visually similar to an "m" with its top-left corner slightly turned upward, holds no significant cultural associations but is technically vital for accurate representation of specific words or phrases in certain languages. Its primary role lies in modifying the appearance of adjacent letters to convey unique meanings or sounds, contributing to the richness and diversity of human language as expressed through typography.

How to type the symbol on Windows

Hold Alt and type 7514 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D5A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D5A to binary: 00011101 01011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110101 10011010