SUNDANESE PUNCTUATION BINDU DA SATANGA·U+1CC6

Character Information

Code Point
U+1CC6
HEX
1CC6
Unicode Plane
Basic Multilingual Plane
Category
Other Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B3 86
11100001 10110011 10000110
UTF16 (big Endian)
1C C6
00011100 11000110
UTF16 (little Endian)
C6 1C
11000110 00011100
UTF32 (big Endian)
00 00 1C C6
00000000 00000000 00011100 11000110
UTF32 (little Endian)
C6 1C 00 00
11000110 00011100 00000000 00000000
HTML Entity
᳆
URI Encoded
%E1%B3%86

Description

The Unicode character U+1CC6, known as "SUNDANESE PUNCTUATION BINDU DA SATANGA", holds a significant position in the realm of digital text, particularly within the Sundanese language, which is predominantly spoken in West Java and Banten provinces in Indonesia. It serves a crucial function in the written form of this language by acting as a punctuation mark that separates clauses or phrases within a sentence. The character's role is not only important for readability but also for preserving the linguistic integrity of Sundanese text. This unique punctuation mark reflects the rich cultural and linguistic heritage of Sundanese, showcasing its distinctiveness from other languages. It is imperative to include such characters in digital typography systems to ensure accurate representation and communication of this diverse language, contributing to a more inclusive and culturally enriched digital text landscape.

How to type the symbol on Windows

Hold Alt and type 7366 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1CC6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1CC6 to binary: 00011100 11000110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110011 10000110