SUNDANESE PUNCTUATION BINDU LEU SATANGA·U+1CC4

Character Information

Code Point
U+1CC4
HEX
1CC4
Unicode Plane
Basic Multilingual Plane
Category
Other Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B3 84
11100001 10110011 10000100
UTF16 (big Endian)
1C C4
00011100 11000100
UTF16 (little Endian)
C4 1C
11000100 00011100
UTF32 (big Endian)
00 00 1C C4
00000000 00000000 00011100 11000100
UTF32 (little Endian)
C4 1C 00 00
11000100 00011100 00000000 00000000
HTML Entity
᳄
URI Encoded
%E1%B3%84

Description

The Unicode character U+1CC4 represents the "Sundanese Punctuation Bindu Leu Satanga," which is an essential element in Sundanese language text. This unique punctuation mark serves as a symbol of cultural identity for the Sundanese-speaking people of West Java, Indonesia. In digital text, it functions to separate clauses or phrases and maintains text coherence, similar to how semicolons or commas are used in other languages. The character is essential for accurate and respectful transcription of traditional Sundanese texts, promoting preservation of the language's rich heritage. Although not widely recognized globally, the Sundanese Punctuation Bindu Leu Satanga remains an integral part of the Sundanese writing system, highlighting the importance of Unicode in supporting diverse linguistic and cultural expressions.

How to type the symbol on Windows

Hold Alt and type 7364 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1CC4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1CC4 to binary: 00011100 11000100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110011 10000100