SUNDANESE CONSONANT SIGN PAMINGKAL·U+1BA1

Character Information

Code Point
U+1BA1
HEX
1BA1
Unicode Plane
Basic Multilingual Plane
Category
Spacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AE A1
11100001 10101110 10100001
UTF16 (big Endian)
1B A1
00011011 10100001
UTF16 (little Endian)
A1 1B
10100001 00011011
UTF32 (big Endian)
00 00 1B A1
00000000 00000000 00011011 10100001
UTF32 (little Endian)
A1 1B 00 00
10100001 00011011 00000000 00000000
HTML Entity
ᮡ
URI Encoded
%E1%AE%A1

Description

U+1BA1 is the Unicode code point for the Sundanese Consonant Sign Pamingkal (ᮟ). In digital text, this character serves as a phonetic symbol in the Javanese script, which is primarily used to represent the Sundanese language spoken by millions of people in West Java, Indonesia. The Sundanese script is derived from the Old Javanese script, featuring unique consonant and vowel signs that are differentiated by diacritical marks. As a consonant sign in the script, ᮟ represents the phoneme /p/, playing a vital role in accurately representing the Sundanese language's phonetic structure. This character is essential for maintaining the linguistic integrity and cultural heritage of the Sundanese people, as it enables accurate representation and communication of their unique language in digital formats.

How to type the symbol on Windows

Hold Alt and type 7073 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1BA1. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1BA1 to binary: 00011011 10100001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101110 10100001