SUNDANESE LETTER LEU·U+1BBC

Character Information

Code Point
U+1BBC
HEX
1BBC
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AE BC
11100001 10101110 10111100
UTF16 (big Endian)
1B BC
00011011 10111100
UTF16 (little Endian)
BC 1B
10111100 00011011
UTF32 (big Endian)
00 00 1B BC
00000000 00000000 00011011 10111100
UTF32 (little Endian)
BC 1B 00 00
10111100 00011011 00000000 00000000
HTML Entity
ᮼ
URI Encoded
%E1%AE%BC

Description

U+1BBC is the Unicode character code for Sundanese Letter Leu. It is a crucial element in the Sundanese language's script, which primarily serves as a medium of communication in West Java and Banten, Indonesia. In digital text, the character plays a vital role in accurately representing and preserving the linguistic features of Sundanese, thereby ensuring the integrity of cultural and historical contexts embedded within the language. The Sundanese script is derived from the Old Javanese script and incorporates Latin alphabet elements, highlighting its unique typographic characteristics. As a part of the Unicode Standard, U+1BBC ensures that Sundanese text can be efficiently encoded, transmitted, and displayed across various digital platforms, fostering communication and promoting cultural diversity.

How to type the symbol on Windows

Hold Alt and type 7100 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1BBC. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1BBC to binary: 00011011 10111100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101110 10111100