LATIN SUBSCRIPT SMALL LETTER M·U+2098

Character Information

Code Point
U+2098
HEX
2098
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 82 98
11100010 10000010 10011000
UTF16 (big Endian)
20 98
00100000 10011000
UTF16 (little Endian)
98 20
10011000 00100000
UTF32 (big Endian)
00 00 20 98
00000000 00000000 00100000 10011000
UTF32 (little Endian)
98 20 00 00
10011000 00100000 00000000 00000000
HTML Entity
ₘ
URI Encoded
%E2%82%98

Description

The Unicode character U+2098, known as LATIN SUBSCRIPT SMALL LETTER M, plays a significant role in digital text by providing the capability to represent the lowercase letter 'm' in a subscripted form. This can be particularly useful for expressing mathematical and chemical notations that require the use of subscripts in their notation. For instance, in chemistry, it is often used to denote isotopes or elements with multiple subatomic particles such as neutrons or protons. In mathematics, the character may appear in algebraic expressions, especially when the base of a logarithm is 10 (as in base-10 logarithms). Despite being less commonly used than its counterpart, LATIN SUBSCRIPT CAPITAL LETTER M (U+2097), U+2098 serves an essential function in digital text for precise and accurate representation of specific notations in various fields.

How to type the symbol on Windows

Hold Alt and type 8344 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2098. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2098 to binary: 00100000 10011000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10000010 10011000