LATIN SUBSCRIPT SMALL LETTER X·U+2093

Character Information

Code Point
U+2093
HEX
2093
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 82 93
11100010 10000010 10010011
UTF16 (big Endian)
20 93
00100000 10010011
UTF16 (little Endian)
93 20
10010011 00100000
UTF32 (big Endian)
00 00 20 93
00000000 00000000 00100000 10010011
UTF32 (little Endian)
93 20 00 00
10010011 00100000 00000000 00000000
HTML Entity
ₓ
URI Encoded
%E2%82%93

Description

U+2093, the Latin Subscript Small Letter X, is a specialized character in Unicode typography used predominantly for scientific and mathematical notation in digital text. Its primary function lies in representing a small lowercase 'x' positioned below the baseline of a text string. This allows for clearer and more precise expression of concepts requiring subscripts within equations or technical documents. While its usage may be less widespread compared to other Unicode characters, it holds significant value in specific fields such as chemistry, physics, and mathematics. The Latin Subscript Small Letter X contributes to the accuracy and clarity of information shared across various industries, ensuring efficient communication of complex ideas.

How to type the symbol on Windows

Hold Alt and type 8339 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2093. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2093 to binary: 00100000 10010011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10000010 10010011