RIGHTWARDS ARROW THROUGH X·U+2947

Character Information

Code Point
U+2947
HEX
2947
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A5 87
11100010 10100101 10000111
UTF16 (big Endian)
29 47
00101001 01000111
UTF16 (little Endian)
47 29
01000111 00101001
UTF32 (big Endian)
00 00 29 47
00000000 00000000 00101001 01000111
UTF32 (little Endian)
47 29 00 00
01000111 00101001 00000000 00000000
HTML Entity
⥇
URI Encoded
%E2%A5%87

Description

The Unicode character U+2947, known as the RIGHTWARDS ARROW THROUGH X, is a specialized symbol with significant roles in digital text representation. It typically serves to illustrate a transformation or mapping in mathematics, computer science, and engineering. This character can be seen in contexts such as programming languages, scientific documents, and technical manuals where the need arises to showcase relationships between specific variables or data points. Although it may not have widespread cultural, linguistic, or technical significance, its usage is crucial in specific academic and professional domains due to its ability to precisely depict certain operations or directions. In these contexts, the RIGHTWARDS ARROW THROUGH X serves as an indispensable tool for clear and accurate communication of complex ideas and processes.

How to type the symbol on Windows

Hold Alt and type 10567 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2947. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2947 to binary: 00101001 01000111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10100101 10000111