RIGHTWARDS ARROW WITH TAIL WITH DOUBLE VERTICAL STROKE·U+2915

Character Information

Code Point
U+2915
HEX
2915
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A4 95
11100010 10100100 10010101
UTF16 (big Endian)
29 15
00101001 00010101
UTF16 (little Endian)
15 29
00010101 00101001
UTF32 (big Endian)
00 00 29 15
00000000 00000000 00101001 00010101
UTF32 (little Endian)
15 29 00 00
00010101 00101001 00000000 00000000
HTML Entity
⤕
URI Encoded
%E2%A4%95

Description

U+2915 is a Unicode character known as the "RIGHTWARDS ARROW WITH TAIL WITH DOUBLE VERTICAL STROKE". This symbol is typically used in digital text to represent an arrow pointing to the right, with an added tail and double vertical strokes. Its primary use is within mathematical and technical contexts to depict various types of arrows or flows in diagrams, charts, and equations. Due to its specialized nature, it is less commonly seen in everyday language or general typography, but its presence can significantly enhance the readability and understanding of certain concepts. As a unique symbol that combines both an arrow and a tail with double vertical strokes, it adds an element of precision and clarity for those familiar with this specific notation system.

How to type the symbol on Windows

Hold Alt and type 10517 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2915. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2915 to binary: 00101001 00010101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10100100 10010101