RIGHTWARDS TWO-HEADED ARROW WITH TAIL WITH DOUBLE VERTICAL STROKE·U+2918

Character Information

Code Point
U+2918
HEX
2918
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A4 98
11100010 10100100 10011000
UTF16 (big Endian)
29 18
00101001 00011000
UTF16 (little Endian)
18 29
00011000 00101001
UTF32 (big Endian)
00 00 29 18
00000000 00000000 00101001 00011000
UTF32 (little Endian)
18 29 00 00
00011000 00101001 00000000 00000000
HTML Entity
⤘
URI Encoded
%E2%A4%98

Description

The character U+2918, known as "RIGHTWARDS TWO-HEADED ARROW WITH TAIL WITH DOUBLE VERTICAL STROKE," is a typographical symbol found in the Unicode standard. It is utilized in digital text to represent a specific mathematical or logical operation, where it signifies a rightward flow of two concurrent processes with an additional tail that has double vertical strokes. This unique symbol finds its application predominantly in fields like computer science, mathematics, and engineering, aiding in visual representation of complex algorithms and computations. Although this particular character may not be widely used or recognized outside these technical domains, it plays a crucial role in the accurate and efficient communication of certain ideas that cannot be effectively conveyed using common text alone. Its double vertical stroke distinguishes it from other arrows in Unicode, enhancing its utility and specificity within its intended contexts.

How to type the symbol on Windows

Hold Alt and type 10520 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2918. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2918 to binary: 00101001 00011000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10100100 10011000