GREATER-THAN OR SLANTED EQUAL TO WITH DOT INSIDE·U+2A80

Character Information

Code Point
U+2A80
HEX
2A80
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AA 80
11100010 10101010 10000000
UTF16 (big Endian)
2A 80
00101010 10000000
UTF16 (little Endian)
80 2A
10000000 00101010
UTF32 (big Endian)
00 00 2A 80
00000000 00000000 00101010 10000000
UTF32 (little Endian)
80 2A 00 00
10000000 00101010 00000000 00000000
HTML Entity
⪀
URI Encoded
%E2%AA%80

Description

The Unicode character U+2A80 represents the "Greater-Than Or Slanted Equal To With Dot Inside" symbol. This typographical mark is often used in digital text to denote a mathematical relation where an expression is greater than or equal to another expression, particularly in computer programming and mathematical notation. The symbol resembles the standard greater-than sign (U+003E), but features a distinctive slanted orientation and a dot placed inside the leftward-pointing angle of the symbol. Although not widely used across various languages, its inclusion in Unicode ensures that it can be utilized within any digital text environment to maintain consistent representation and meaning across different platforms and systems.

How to type the symbol on Windows

Hold Alt and type 10880 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A80. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A80 to binary: 00101010 10000000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101010 10000000