INTEGRAL WITH LEFTWARDS ARROW WITH HOOK·U+2A17

Character Information

Code Point
U+2A17
HEX
2A17
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A8 97
11100010 10101000 10010111
UTF16 (big Endian)
2A 17
00101010 00010111
UTF16 (little Endian)
17 2A
00010111 00101010
UTF32 (big Endian)
00 00 2A 17
00000000 00000000 00101010 00010111
UTF32 (little Endian)
17 2A 00 00
00010111 00101010 00000000 00000000
HTML Entity
⨗
URI Encoded
%E2%A8%97

Description

The Unicode character U+2A17, known as INTEGRAL WITH LEFTWARDS ARROW WITH HOOK, is a mathematical symbol that holds significant importance in digital text, particularly in the realm of mathematics and scientific notation. Its primary usage is to denote an integral with a leftwards arrow representing the concept of "taking the derivative", along with a hook-like structure implying additional operations or processes may be involved. This character enables more precise communication of complex mathematical concepts in digital text, facilitating clarity and reducing misinterpretation among mathematicians, scientists, and engineers who rely on this level of specificity for their work. As part of the Unicode Standard, U+2A17 ensures that this symbol can be accurately represented across various platforms and software applications, maintaining consistency in typography and facilitating seamless communication within the global community of professionals using these mathematical symbols.

How to type the symbol on Windows

Hold Alt and type 10775 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A17. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A17 to binary: 00101010 00010111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101000 10010111