LOGICAL AND WITH MIDDLE STEM·U+2A5A

Character Information

Code Point
U+2A5A
HEX
2A5A
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 9A
11100010 10101001 10011010
UTF16 (big Endian)
2A 5A
00101010 01011010
UTF16 (little Endian)
5A 2A
01011010 00101010
UTF32 (big Endian)
00 00 2A 5A
00000000 00000000 00101010 01011010
UTF32 (little Endian)
5A 2A 00 00
01011010 00101010 00000000 00000000
HTML Entity
⩚
URI Encoded
%E2%A9%9A

Description

The Unicode character U+2A5A represents the "LOGICAL AND WITH MIDDLE STEM" symbol. In digital text, this character is typically employed in mathematical expressions to denote a logical conjunction between two statements or conditions. Although it bears resemblance to the ampersand (&) symbol, it serves as an explicit representation of a logical operation rather than a general-purpose punctuation mark. This character holds significance in linguistic and technical contexts where precise expression of logical operations is crucial, such as programming, formal logic, and mathematical notation. Its inclusion helps avoid ambiguity, thereby facilitating clearer communication and less room for error.

How to type the symbol on Windows

Hold Alt and type 10842 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A5A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A5A to binary: 00101010 01011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10011010