LOGICAL OR WITH DOT ABOVE·U+2A52

Character Information

Code Point
U+2A52
HEX
2A52
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 92
11100010 10101001 10010010
UTF16 (big Endian)
2A 52
00101010 01010010
UTF16 (little Endian)
52 2A
01010010 00101010
UTF32 (big Endian)
00 00 2A 52
00000000 00000000 00101010 01010010
UTF32 (little Endian)
52 2A 00 00
01010010 00101010 00000000 00000000
HTML Entity
⩒
URI Encoded
%E2%A9%92

Description

The Unicode character U+2A52, known as LOGICAL OR WITH DOT ABOVE, is a symbol that holds significance in the realm of digital text and mathematical expressions. This typographical representation is often employed to indicate the logical "or" operation within computer science and programming contexts. Its usage allows for greater clarity when communicating complex Boolean logic or data processing concepts. Though not widely known outside of specialized fields, this character plays a crucial role in the accurate and efficient expression of certain technical ideas. Despite its obscure nature, the LOGICAL OR WITH DOT ABOVE holds immense value as an essential tool in digital text for those working in computer science, engineering, or related disciplines.

How to type the symbol on Windows

Hold Alt and type 10834 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A52. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A52 to binary: 00101010 01010010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10010010