PLUS SIGN WITH BLACK TRIANGLE·U+2A28

Character Information

Code Point
U+2A28
HEX
2A28
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A8 A8
11100010 10101000 10101000
UTF16 (big Endian)
2A 28
00101010 00101000
UTF16 (little Endian)
28 2A
00101000 00101010
UTF32 (big Endian)
00 00 2A 28
00000000 00000000 00101010 00101000
UTF32 (little Endian)
28 2A 00 00
00101000 00101010 00000000 00000000
HTML Entity
⨨
URI Encoded
%E2%A8%A8

Description

The Unicode character U+2A28, known as the Plus Sign with Black Triangle (⩷), is a relatively rare typographical symbol that combines a plus sign (+) and a black triangle. In digital text, this character often serves to indicate an operation or action involving both addition and some form of triangulation or directional movement. Although it doesn't have a specific cultural, linguistic, or technical context associated with its usage, the Plus Sign with Black Triangle can be found in mathematical equations, engineering diagrams, or scientific notations where the combination of these symbols is relevant. Despite being less commonly used compared to other Unicode characters, U+2A28 offers a unique visual element that can enhance the clarity and understanding of certain concepts in specific contexts.

How to type the symbol on Windows

Hold Alt and type 10792 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A28. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A28 to binary: 00101010 00101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101000 10101000