SLANTED EQUAL TO OR LESS-THAN WITH DOT INSIDE·U+2A97

Character Information

Code Point
U+2A97
HEX
2A97
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AA 97
11100010 10101010 10010111
UTF16 (big Endian)
2A 97
00101010 10010111
UTF16 (little Endian)
97 2A
10010111 00101010
UTF32 (big Endian)
00 00 2A 97
00000000 00000000 00101010 10010111
UTF32 (little Endian)
97 2A 00 00
10010111 00101010 00000000 00000000
HTML Entity
⪗
URI Encoded
%E2%AA%97

Description

The Unicode character U+2A97, known as the "Slanted Equal To Or Less-Than With Dot Inside" (⋖), plays a unique role in digital text representation. This typographical symbol is part of the Miscellaneous Technical category within the Unicode Standard, which consists of various special and technical symbols often used in mathematical or scientific contexts. In its typical usage, this character is employed to represent an inequality, specifically "less than or equal to" in a slanted or oblique format, providing a visually distinct alternative to the standard "less than or equal to" symbol (≤). The presence of a dot inside the symbol serves as a stylistic flourish, adding visual interest and distinguishing it from other inequality symbols. Although U+2A97 does not carry any specific cultural, linguistic, or technical significance beyond its unique appearance, its inclusion in digital text demonstrates the expansive range of expressive options provided by the Unicode Standard.

How to type the symbol on Windows

Hold Alt and type 10903 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A97. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A97 to binary: 00101010 10010111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101010 10010111