Character Information

Code Point
U+2A58
HEX
2A58
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 98
11100010 10101001 10011000
UTF16 (big Endian)
2A 58
00101010 01011000
UTF16 (little Endian)
58 2A
01011000 00101010
UTF32 (big Endian)
00 00 2A 58
00000000 00000000 00101010 01011000
UTF32 (little Endian)
58 2A 00 00
01011000 00101010 00000000 00000000
HTML Entity
⩘
URI Encoded
%E2%A9%98

Description

The Unicode character U+2A58, known as the SLOPING LARGE AND, is a typographical symbol used primarily in digital text for its mathematical representation of an inequality. Specifically, it is employed to denote "greater than or equal to" when combined with an equals sign (=), and "less than or equal to" when paired with a less-than sign (<). This symbol finds application in various fields such as computer science, engineering, and mathematics, where precise expressions of relationships between quantities are crucial. Although the character is not language-specific, it adheres to general typographic conventions that facilitate comprehension across different linguistic contexts. Due to its specific usage and lack of direct cultural or linguistic relevance, the SLOPING LARGE AND does not carry any notable cultural connotations. However, its utility in representing essential mathematical principles ensures its continued importance in digital communication across diverse fields.

How to type the symbol on Windows

Hold Alt and type 10840 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A58. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A58 to binary: 00101010 01011000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10011000