SUPERSET ABOVE SUPERSET·U+2AD6

Character Information

Code Point
U+2AD6
HEX
2AD6
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AB 96
11100010 10101011 10010110
UTF16 (big Endian)
2A D6
00101010 11010110
UTF16 (little Endian)
D6 2A
11010110 00101010
UTF32 (big Endian)
00 00 2A D6
00000000 00000000 00101010 11010110
UTF32 (little Endian)
D6 2A 00 00
11010110 00101010 00000000 00000000
HTML Entity
⫖
URI Encoded
%E2%AB%96

Description

The character U+2AD6, known as the "Superset Above Superset" (SAS), holds a significant role within the realm of Unicode typography. Its primary usage is in mathematical and computer science contexts, specifically when dealing with sets theory. In this domain, SAS allows digital text to represent a superset relationship between two sets, where one set encompasses all elements from both itself and another set. This unique character aids in the clear representation of hierarchical relationships within mathematical equations or algorithms, contributing to greater clarity and efficiency when communicating complex concepts. While U+2AD6 may not be commonly seen outside of these niche fields, it serves as a crucial tool for those working with supersets and their intricate relationships.

How to type the symbol on Windows

Hold Alt and type 10966 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2AD6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2AD6 to binary: 00101010 11010110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101011 10010110