THREE CONSECUTIVE EQUALS SIGNS·U+2A76

Character Information

Code Point
U+2A76
HEX
2A76
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 B6
11100010 10101001 10110110
UTF16 (big Endian)
2A 76
00101010 01110110
UTF16 (little Endian)
76 2A
01110110 00101010
UTF32 (big Endian)
00 00 2A 76
00000000 00000000 00101010 01110110
UTF32 (little Endian)
76 2A 00 00
01110110 00101010 00000000 00000000
HTML Entity
⩶
URI Encoded
%E2%A9%B6

Description

U+2A76 is a Unicode character code that represents the "THREE CONSECUTIVE EQUALS SIGNS" (‼). This typographical symbol is typically used in digital text for various purposes, such as indicating an error or unexpected result in programming languages, marking a break or separation in written content, or emphasizing a particular point. While it does not have any specific cultural, linguistic, or technical context, its usage can vary depending on the application and language used. It is important to note that this character is not widely used in everyday text but holds significance in specific scenarios, such as debugging or formatting code.

How to type the symbol on Windows

Hold Alt and type 10870 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A76. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A76 to binary: 00101010 01110110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10110110