TWO LOGICAL AND OPERATOR·U+2A07

Character Information

Code Point
U+2A07
HEX
2A07
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A8 87
11100010 10101000 10000111
UTF16 (big Endian)
2A 07
00101010 00000111
UTF16 (little Endian)
07 2A
00000111 00101010
UTF32 (big Endian)
00 00 2A 07
00000000 00000000 00101010 00000111
UTF32 (little Endian)
07 2A 00 00
00000111 00101010 00000000 00000000
HTML Entity
⨇
URI Encoded
%E2%A8%87

Description

The Unicode character U+2A07 is known as the TWO LOGICAL AND OPERATOR. This specific symbol has a crucial role in digital text, particularly in programming languages and logical expressions. It acts as a binary operator, performing logical conjunction on two operands. In essence, it returns true only if both of its operands are true, thereby acting like a standard "AND" operator used in most programming languages. The character can be found within the Unicode Character Block for Mathematical Operators, signifying its role in mathematical expressions and logic gates. Though not as widely recognized or utilized in everyday text, U+2A07 plays an essential part in various digital contexts, including computer programming, symbolic mathematics, and logical circuits.

How to type the symbol on Windows

Hold Alt and type 10759 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A07. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A07 to binary: 00101010 00000111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101000 10000111