UNION ABOVE INTERSECTION·U+2A46

Character Information

Code Point
U+2A46
HEX
2A46
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 86
11100010 10101001 10000110
UTF16 (big Endian)
2A 46
00101010 01000110
UTF16 (little Endian)
46 2A
01000110 00101010
UTF32 (big Endian)
00 00 2A 46
00000000 00000000 00101010 01000110
UTF32 (little Endian)
46 2A 00 00
01000110 00101010 00000000 00000000
HTML Entity
⩆
URI Encoded
%E2%A9%86

Description

The Unicode character U+2A46, known as "Union Above Intersection," is a mathematical symbol used to represent the union of sets, which is an operation that combines elements from multiple sets while removing duplicates. This typographical symbol plays a significant role in digital text, especially within the realm of mathematics and computer science, where it helps to express complex relationships between different data points or concepts accurately. U+2A46 Union Above Intersection is often used in set theory, Venn diagrams, and other visual representations of abstract concepts. It is derived from traditional mathematical symbols, and its digital representation is a vital part of clear communication within technical and academic fields.

How to type the symbol on Windows

Hold Alt and type 10822 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A46. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A46 to binary: 00101010 01000110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10000110