LEFT DOTTED SUBSTITUTION BRACKET·U+2E04

Character Information

Code Point
U+2E04
HEX
2E04
Unicode Plane
Basic Multilingual Plane
Category
Initial Quote

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 B8 84
11100010 10111000 10000100
UTF16 (big Endian)
2E 04
00101110 00000100
UTF16 (little Endian)
04 2E
00000100 00101110
UTF32 (big Endian)
00 00 2E 04
00000000 00000000 00101110 00000100
UTF32 (little Endian)
04 2E 00 00
00000100 00101110 00000000 00000000
HTML Entity
⸄
URI Encoded
%E2%B8%84

Description

The Left Dotted Substitution Bracket (U+2E04) is a lesser-known Unicode character that serves a specific role in digital text. It is primarily used in the context of marking the beginning or end of a substitutable block of text, particularly in specialized typesetting and document formatting. The Left Dotted Substitution Bracket, along with its right counterpart (U+2E05), is essential for ensuring accurate and consistent formatting when substituting or replacing specific blocks of text within documents. In certain niche applications, such as mathematical or scientific texts, these characters may play a more prominent role in delineating sections of the document for efficient editing and formatting. However, due to its limited usage and less common contexts, the Left Dotted Substitution Bracket is not widely recognized by most digital text users or typography enthusiasts.

How to type the symbol on Windows

Hold Alt and type 11780 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2E04. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2E04 to binary: 00101110 00000100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111000 10000100