LEFT DOUBLE PARENTHESIS·U+2E28

Character Information

Code Point
U+2E28
HEX
2E28
Unicode Plane
Basic Multilingual Plane
Category
Open Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 B8 A8
11100010 10111000 10101000
UTF16 (big Endian)
2E 28
00101110 00101000
UTF16 (little Endian)
28 2E
00101000 00101110
UTF32 (big Endian)
00 00 2E 28
00000000 00000000 00101110 00101000
UTF32 (little Endian)
28 2E 00 00
00101000 00101110 00000000 00000000
HTML Entity
⸨
URI Encoded
%E2%B8%A8

Description

The Unicode character U+2E28, also known as the Left Double Parenthesis, plays a significant role in digital typography. It is used to denote mathematical parentheses for complex mathematical expressions, particularly in the TeX typesetting system and LaTeX markup language. While it may not be commonly utilized in everyday digital text, its precise function is essential in the realm of mathematics and scientific writing. The Left Double Parenthesis is a vital tool in expressing nested or compound equations, contributing to clarity and accuracy in these advanced fields of study. There are no notable cultural, linguistic, or technical contexts associated with this specific Unicode character, as its primary purpose is functional rather than symbolic or expressive.

How to type the symbol on Windows

Hold Alt and type 11816 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2E28. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2E28 to binary: 00101110 00101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111000 10101000