TOP RIGHT HALF BRACKET·U+2E23

Character Information

Code Point
U+2E23
HEX
2E23
Unicode Plane
Basic Multilingual Plane
Category
Close Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 B8 A3
11100010 10111000 10100011
UTF16 (big Endian)
2E 23
00101110 00100011
UTF16 (little Endian)
23 2E
00100011 00101110
UTF32 (big Endian)
00 00 2E 23
00000000 00000000 00101110 00100011
UTF32 (little Endian)
23 2E 00 00
00100011 00101110 00000000 00000000
HTML Entity
⸣
URI Encoded
%E2%B8%A3

Description

The Unicode character U+2E23 represents the "TOP RIGHT HALF BRACKET" in digital text. This character is often employed in mathematical notation and symbolic expressions to delineate segments of content. For instance, it can denote a section or portion within an equation or formula, or even signify a specific boundary in a sequence of data. Despite its name suggesting a positioning on the upper-right corner of a bracket, U+2E23 is not restricted to this placement and may be used anywhere within text where its function necessitates. In terms of cultural, linguistic, or technical contexts, there are none that are particularly notable for this character. Its usage relies heavily on its ability to clearly demarcate sections of text in various contexts, making it an essential tool for precision in digital communication.

How to type the symbol on Windows

Hold Alt and type 11811 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2E23. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2E23 to binary: 00101110 00100011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111000 10100011