TAI LE LETTER I·U+1964

Character Information

Code Point
U+1964
HEX
1964
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A5 A4
11100001 10100101 10100100
UTF16 (big Endian)
19 64
00011001 01100100
UTF16 (little Endian)
64 19
01100100 00011001
UTF32 (big Endian)
00 00 19 64
00000000 00000000 00011001 01100100
UTF32 (little Endian)
64 19 00 00
01100100 00011001 00000000 00000000
HTML Entity
ᥤ
URI Encoded
%E1%A5%A4

Description

The Unicode character U+1964, also known as TAI LE LETTER I, is a letter from the Tai Le script, which was developed in the early 20th century by Thuy Tien Le for the Tai Le language spoken primarily in Vietnam. It is typically utilized in digital text to represent the sound 'ɨ' or 'ɪ', depending on its position within a word and its adjacent consonants. The TAI LE LETTER I holds significant cultural importance, as it represents a unique linguistic feature of the Tai Le language, which has been historically overlooked by scholars due to limited written documentation. Its inclusion in the Unicode Standard ensures that the richness of this language is preserved and accessible for digital communication, research, and preservation efforts.

How to type the symbol on Windows

Hold Alt and type 6500 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1964. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1964 to binary: 00011001 01100100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100101 10100100