TAI LE LETTER NGA·U+1952

Character Information

Code Point
U+1952
HEX
1952
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A5 92
11100001 10100101 10010010
UTF16 (big Endian)
19 52
00011001 01010010
UTF16 (little Endian)
52 19
01010010 00011001
UTF32 (big Endian)
00 00 19 52
00000000 00000000 00011001 01010010
UTF32 (little Endian)
52 19 00 00
01010010 00011001 00000000 00000000
HTML Entity
ᥒ
URI Encoded
%E1%A5%92

Description

U+1952 is the Unicode code point for TAI LE LETTER NGA, a character from the Tai Le script, which is primarily used in writing the Tai Le language. The TAI LE LETTER NGA holds a significant role in digital text as it represents a phoneme or unit of sound in the Tai Le language. It's an essential component of the written form of this lesser-known but fascinating Southeast Asian language, which is primarily spoken by the Tai Le people in Vietnam. The TAI LE LETTER NGA and other characters from the Tai Le script contribute to the rich cultural and linguistic heritage of the communities that speak the language, providing a unique means of written expression for their literature, history, and traditions.

How to type the symbol on Windows

Hold Alt and type 6482 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1952. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1952 to binary: 00011001 01010010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100101 10010010