TAI LE LETTER O·U+1969

Character Information

Code Point
U+1969
HEX
1969
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A5 A9
11100001 10100101 10101001
UTF16 (big Endian)
19 69
00011001 01101001
UTF16 (little Endian)
69 19
01101001 00011001
UTF32 (big Endian)
00 00 19 69
00000000 00000000 00011001 01101001
UTF32 (little Endian)
69 19 00 00
01101001 00011001 00000000 00000000
HTML Entity
ᥩ
URI Encoded
%E1%A5%A9

Description

The Unicode character U+1969 represents the Tai Le letter 'O', a unique glyph found in the Tai Le script. Developed by the Tai Le people of Southwestern China's Yunnan Province, this script is primarily used for writing their distinct language, which belongs to the Loloish branch of the Tibeto-Burman language family. The Tai Le letter 'O' (U+1969) plays a crucial role in digital text by enabling accurate representation and preservation of the language's rich cultural heritage. This character is part of Unicode Block "Tai Le", which consists of 27 code points ranging from U+1960 to U+197F, reflecting the comprehensive coverage of the Tai Le script in digital communication. The inclusion of this character and others like it in the Unicode Standard demonstrates a commitment to supporting lesser-known languages and scripts, fostering diversity and inclusivity within global digital text.

How to type the symbol on Windows

Hold Alt and type 6505 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1969. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1969 to binary: 00011001 01101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100101 10101001