TAI LE LETTER PA·U+1959

Character Information

Code Point
U+1959
HEX
1959
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A5 99
11100001 10100101 10011001
UTF16 (big Endian)
19 59
00011001 01011001
UTF16 (little Endian)
59 19
01011001 00011001
UTF32 (big Endian)
00 00 19 59
00000000 00000000 00011001 01011001
UTF32 (little Endian)
59 19 00 00
01011001 00011001 00000000 00000000
HTML Entity
ᥙ
URI Encoded
%E1%A5%99

Description

The Unicode character U+1959, known as TAI LE LETTER PA, is a specialized letter used primarily within the Tai Le language, spoken by indigenous communities in Southern Vietnam. In digital text, this character serves to represent a unique phoneme or sound in the Tai Le language and is essential for accurate transcription of spoken language into written form. U+1959 plays a crucial role in preserving linguistic heritage and facilitating communication among speakers of the Tai Le language. As the TAI LE LETTER PA character is not widely used outside its specific cultural context, it remains relatively obscure to many people familiar with other languages or scripts. This character is essential for accurate transcription and representation of the unique linguistic features of the Tai Le language in digital platforms and text-based communication.

How to type the symbol on Windows

Hold Alt and type 6489 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1959. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1959 to binary: 00011001 01011001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100101 10011001