TAI THAM CONSONANT SIGN HIGH RATHA OR LOW PA·U+1A5B

Character Information

Code Point
U+1A5B
HEX
1A5B
Unicode Plane
Basic Multilingual Plane
Category
Nonspacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A9 9B
11100001 10101001 10011011
UTF16 (big Endian)
1A 5B
00011010 01011011
UTF16 (little Endian)
5B 1A
01011011 00011010
UTF32 (big Endian)
00 00 1A 5B
00000000 00000000 00011010 01011011
UTF32 (little Endian)
5B 1A 00 00
01011011 00011010 00000000 00000000
HTML Entity
ᩛ
URI Encoded
%E1%A9%9B

Description

U+1A5B is a Unicode character that represents the TAI THAM CONSONANT SIGN HIGH RATHA OR LOW PA in digital text. This particular character plays an essential role in the Thai language, specifically within the Tham script, which was used during the Dvaravati and Sukhothai periods. The Tham script is a precursor to the modern Thai script, and although not widely used today, it holds significant cultural and historical value. U+1A5B, or ᜫ in Unicode, is an important character for linguists, historians, and typographers who study the development of the Thai language and its various scripts over time. Its usage is primarily in academic and research contexts to accurately transcribe and analyze ancient Thai texts, providing a window into the history and evolution of this rich language.

How to type the symbol on Windows

Hold Alt and type 6747 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A5B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A5B to binary: 00011010 01011011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101001 10011011