TAI THAM HORA DIGIT THREE·U+1A83

Character Information

Code Point
U+1A83
HEX
1A83
Unicode Plane
Basic Multilingual Plane
Category
Decimal Digit Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AA 83
11100001 10101010 10000011
UTF16 (big Endian)
1A 83
00011010 10000011
UTF16 (little Endian)
83 1A
10000011 00011010
UTF32 (big Endian)
00 00 1A 83
00000000 00000000 00011010 10000011
UTF32 (little Endian)
83 1A 00 00
10000011 00011010 00000000 00000000
HTML Entity
᪃
URI Encoded
%E1%AA%83

Description

U+1A83 is the Unicode code point for TAI THAM HORA DIGIT THREE, a character primarily used in digital text representation within the Tai Tham (or Khamti) script. This script is predominantly utilized in the Khamti language, spoken by the Khamti people residing mainly in India's Arunachal Pradesh and Nagaland states, as well as in Myanmar. The TAI THAM HORA DIGIT THREE specifically serves as a numeral three in this script, representing a quantity or order. Despite being lesser-known compared to other scripts, the TAI THAM HORA DIGIT THREE and the Khamti script play a crucial role in preserving and promoting the linguistic heritage of the Khamti people.

How to type the symbol on Windows

Hold Alt and type 6787 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A83. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A83 to binary: 00011010 10000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101010 10000011