TAI THAM LETTER HIGH FA·U+1A3A

Character Information

Code Point
U+1A3A
HEX
1A3A
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A8 BA
11100001 10101000 10111010
UTF16 (big Endian)
1A 3A
00011010 00111010
UTF16 (little Endian)
3A 1A
00111010 00011010
UTF32 (big Endian)
00 00 1A 3A
00000000 00000000 00011010 00111010
UTF32 (little Endian)
3A 1A 00 00
00111010 00011010 00000000 00000000
HTML Entity
ᨺ
URI Encoded
%E1%A8%BA

Description

The Unicode character U+1A3A, TAI THAM LETTER HIGH FA, is an essential component of the Tai Tham script, which belongs to the Tham Sript family. This script is primarily used for writing the Kham Miwok language in the Indian states of Meghalaya and Assam. U+1A3A represents a phonetic value and is used in digital text to accurately transcribe and convey the intended meaning of words and sentences in this language. The character plays a vital role in preserving cultural heritage, promoting linguistic diversity, and facilitating communication among speakers of Kham Miwok.

How to type the symbol on Windows

Hold Alt and type 6714 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A3A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A3A to binary: 00011010 00111010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101000 10111010