TAI THAM LETTER HIGH THA·U+1A33

Character Information

Code Point
U+1A33
HEX
1A33
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A8 B3
11100001 10101000 10110011
UTF16 (big Endian)
1A 33
00011010 00110011
UTF16 (little Endian)
33 1A
00110011 00011010
UTF32 (big Endian)
00 00 1A 33
00000000 00000000 00011010 00110011
UTF32 (little Endian)
33 1A 00 00
00110011 00011010 00000000 00000000
HTML Entity
ᨳ
URI Encoded
%E1%A8%B3

Description

U+1A33, TAI THAM LETTER HIGH THA, is a typographical character that plays a significant role in the digital representation of the Thai language. This Unicode character is part of the Thai script, which belongs to the Tai-Muan group of scripts within the larger Tai writing system. In its typical usage, TAI THAM LETTER HIGH THA is used to represent the voiceless alveolar fricative /ʃ/ sound in the Thai language. Its accurate digital representation is essential for proper text rendering and readability in digital platforms, ensuring that the nuances of the Thai language are maintained. U+1A33 contributes to the linguistic richness and cultural heritage of Thailand, where the Thai script has been used for over seven centuries. In summation, U+1A33, TAI THAM LETTER HIGH THA, is a vital character in digital typography that ensures accurate representation and communication of the Thai language within the context of its cultural and linguistic heritage.

How to type the symbol on Windows

Hold Alt and type 6707 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A33. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A33 to binary: 00011010 00110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101000 10110011