TAI THAM LETTER LOW CA·U+1A29

Character Information

Code Point
U+1A29
HEX
1A29
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A8 A9
11100001 10101000 10101001
UTF16 (big Endian)
1A 29
00011010 00101001
UTF16 (little Endian)
29 1A
00101001 00011010
UTF32 (big Endian)
00 00 1A 29
00000000 00000000 00011010 00101001
UTF32 (little Endian)
29 1A 00 00
00101001 00011010 00000000 00000000
HTML Entity
ᨩ
URI Encoded
%E1%A8%A9

Description

The Unicode character U+1A29, known as "TAI THAM LETTER LOW CA", holds a significant position in the realm of digital text for its use in the Thai script. It is part of the Tai Tham writing system, which has been employed primarily in the northeastern region of Thailand, known as Isan, as well as in surrounding countries like Laos and Cambodia where it is also used by ethnic Thai communities. The character U+1A29 specifically represents the phoneme /a/, and its use aids in the representation of the wide range of vowel sounds that are unique to these languages. While its role may be limited in global digital communication, this character plays an essential part in preserving and promoting the linguistic heritage of these regions.

How to type the symbol on Windows

Hold Alt and type 6697 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A29. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A29 to binary: 00011010 00101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101000 10101001