TAI THAM LETTER LOW CHA·U+1A2B

Character Information

Code Point
U+1A2B
HEX
1A2B
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A8 AB
11100001 10101000 10101011
UTF16 (big Endian)
1A 2B
00011010 00101011
UTF16 (little Endian)
2B 1A
00101011 00011010
UTF32 (big Endian)
00 00 1A 2B
00000000 00000000 00011010 00101011
UTF32 (little Endian)
2B 1A 00 00
00101011 00011010 00000000 00000000
HTML Entity
ᨫ
URI Encoded
%E1%A8%AB

Description

U+1A2B, TAI THAM LETTER LOW CHA, is a typographical character found within the Unicode Standard. It serves as a crucial element in digital text representation for the Tai Tham script, which is primarily used in northeastern Thailand. The script's origins can be traced back to the 19th century when it was developed from the Tai Le script to facilitate the writing of the Thai language. TAI THAM LETTER LOW CHA specifically represents the 'cha' sound, and is utilized within digital text to maintain accuracy in linguistic context. Its inclusion in the Unicode Standard promotes greater accessibility for users and applications working with the Thai language, ensuring the preservation of cultural identity and linguistic nuance.

How to type the symbol on Windows

Hold Alt and type 6699 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A2B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A2B to binary: 00011010 00101011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101000 10101011