TAI THAM LETTER LOW HA·U+1A4C

Character Information

Code Point
U+1A4C
HEX
1A4C
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A9 8C
11100001 10101001 10001100
UTF16 (big Endian)
1A 4C
00011010 01001100
UTF16 (little Endian)
4C 1A
01001100 00011010
UTF32 (big Endian)
00 00 1A 4C
00000000 00000000 00011010 01001100
UTF32 (little Endian)
4C 1A 00 00
01001100 00011010 00000000 00000000
HTML Entity
ᩌ
URI Encoded
%E1%A9%8C

Description

The Unicode character U+1A4C, TAI THAM LETTER LOW HA (ហ), is a crucial component of the Cambodian alphabet. It represents a consonant that combines with other vowel characters to form syllables in the Khmer script. In digital text, this character plays an essential role in preserving and promoting the cultural heritage of the Khmer people, who primarily reside in Cambodia but also have diaspora communities worldwide. The TAI THAM LETTER LOW HA is part of the Cambodian language's rich linguistic history, which dates back to the 7th century CE and has evolved through various eras, including the Angkor period and the French colonial era. In contemporary usage, the character contributes to the accurate representation of traditional and modern Khmer literature, as well as to the development and maintenance of digital resources such as websites, documents, and databases that utilize or cater to the Cambodian language.

How to type the symbol on Windows

Hold Alt and type 6732 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A4C. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A4C to binary: 00011010 01001100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101001 10001100